Suppose that we are not directly given the lengths of the sides of a triangle, rather we are given the coordinates of its vertices. It is especially the case when a triangle is inscribed within a cartesian plane. The coordinates help to locate the triangle.
To find the perimeter when the coordinates of its vertices are given, we need to find the length of the individual sides somehow. To do so, we can calculate the distance between the vertices using the distance formula, and the line segments formed when we connect the vertices are the sides of the triangle itself.
Hence, the length of the line segments joining the vertices will be the same as the length of the sides of the triangle formed.
So now that we have the length of the sides of the triangle in terms of the coordinates of the vertices, we can use the perimeter formula:
Thus, we have found a formula for calculating the perimeter of the triangle whose vertices are given.
Find the perimeter of the triangle whose vertices are located at A(–3, 1), B(2, 1) and C(2, –1).
Solution:
In order to find the length of the perimeter, we need to find the length of the respective sides and we can do so by using the distance formula for all the three vertices.
For the first side AB:
For the second side, BC:
And for the third side, AC:
And now the perimeter can be calculated by adding all these sides:
Hence the perimeter of the triangle whose vertices are A(–3, 1), B(2, 1) and C(2, –1) is units.